# Weird Polar Equation Graphs

Boys, set your calculator to polar mode, and draw a graph of
$r=4sin(3θ)$, then set the first interval of [0,π] and the second one: [0, 2π]
[0,π]
[0,2π]
They looks exactly the same, isn’t it?
And if we take of the integral of these two to find the area, for the graph with interval [0,π], area = 4π, but for the graph with [0,2π] the area is 8π, thus, which one is the “true” one we want to find?